每次抽取后都重新洗牌。计算10000次随机抽取可得到同花的几率。我做的比较复杂,分别累计了四种花色分别出现了几次。
代码语言:javascript
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import random
list=["2","3","4",'5','6','7','8','9','10',"J","Q","K","A"]
list2=["H","C","D","S"]
list3=[]
n=0
a=0
while a<4:
n=0
while n<13:
list3+=[list[n]+list2[a]]
n+=1
a+=1
i=0
r=0
d=0
c=0
s=0
h=0
while i <10000:
random.shuffle(list3)
list4=list3[0:5]
i+=1
for card in list4:
if 'D' in card:
d+=1
if d==5:
r+=1
for card in list4:
if 'H' in card:
h+=1
if h==5:
r+=1
for card in list4:
if 'S' in card:
s+=1
if s==5:
r+=1
for card in list4:
if 'C' in card:
c+=1
if c==5:
r+=1
d=0
c=0
s=0
h=0
print ('Number of natural Flushes:',r)
print('Percentage:',r/100,'%')