Problem Description Ignatius was born in a leap year, so he want to know when he could hold his birthday party. Can you tell him?
Given a positive integers Y which indicate the start year, and a positive integer N, your task is to tell the Nth leap year from year Y.
Note: if year Y is a leap year, then the 1st leap year is year Y.
Input The input contains several test cases. The first line of the input is a single integer T which is the number of test cases. T test cases follow. Each test case contains two positive integers Y and N(1<=N<=10000).
Output For each test case, you should output the Nth leap year from year Y.
Sample Input 3 2005 25 1855 12 2004 10000
Sample Output 2108 1904 43236
Hint： We call year Y a leap year only if (Y%4==0 && Y%100!=0) or Y%400==0.
题意就是：输入一个年份year和一个n，求这个year之后的第n个闰年， 如果year是闰年，则算第一个闰年。
直接暴力做，并没有超时。
import java.util.Scanner;public class Main{
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
int t = sc.nextInt();
while(t-->0){
int year = sc.nextInt();
int n = sc.nextInt();
int nyear = 0;
if((year%4==0&&year%100!=0)|(year%400==0)){
nyear=1;
}//如果year是闰年，nyear就加一
while(nyear<n){//当nyear小于n时，就循环
year++;
if((year%4==0&&year%100!=0)|(year%400==0)){
nyear++;
}//year是闰年，nyear就加加
}
System.out.println(year);
}
}
}
